Egyptian scholastic test (EST) Physics October 2021 with answers and explanation provided by Mrs Hadil Fayzi. EST physics real test questions available with explanation exclusively on sat-act-est.com. Only with us you will find EST physics practice exams with answers and explanation online for free.
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Answer D
KE = ½ mv2
o.96 = ½ x 3 x v2
v= 0.8 m/s
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Answer D
P= fd/t = 1000×300/ 30 = 10000 W
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Answer B
As transverse waves particles vibrate perpendicular to the direction of wave’s propagation
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Answer c Atoms with the same atomic number but with different atomic masses are called isotopes. Isotopes have identical chemical properties, yet have very different nuclear properties
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Answer A
Radioactive decay is the emission of energy in the form of ionizing radiation. The ionizing radiation that is emitted can include alpha particles, beta particles and/or gamma rays.
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Answer A
The figure shows the formation of real and magnified image for a convex lens. It clearly shows that the object is placed in between F and 2F.
EST Physics
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Answer D
Q= m L = 500X10-3 X 3.35X105 = 1.675X105 J
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Answer E
Q = mc t
8000 = 0.4 x c x ( 44.4 – 24.4 )
C= 1 j/g 0 c
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Answer A
= 120 – P
= 120 – 105 X ( 3.5 – 0.2 ) 10-3 = – 210 J ISOBARIC PROCESS ( 1L = 10-3 m3 )
EST Physics
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Answer A
Ruler is used to measure length in cm ,caliper may measure in cm or mm ,micrometer is used to measure small thickness in mm
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Answer D
n = sin Ï´i/ sin Ï´ r
1.5 = sin 30 / sin Ï´ r
Ï´ r = sin 30/ 1.5 = sin-1 ( 1/3 )
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Answer A + 2 q which is the total charge is divided equally between the 2 spheres
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Answer B
V= 2
1500 = 2 / ( 1-0.4 ) d = 450 m
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Answer c
Objects like wool, hair or glass rod tend to give off electrons, and get positively charged. While objects like silk or plastic comb acquire electrons and get negatively charged
EST Physics
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Answer E
F= ma
F= ( 1+ 2 ) a = 3 a a= 1/3 F
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Answer A
d = vi + ½ g t2 d is directly proportional with t2
distance between rocks increases while both are falling
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Answer D
T = 2 Viy / g = 2 Vi sin Ï´ / g = 2×10 sin 30 /10 = 1 sec
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Answer B
total internal reflection takes place at the boundary between two transparent media when a ray of light in a medium of higher index of refraction approaches the other medium at an angle of incidence greater than the critical angle.
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Answer D
R eq = r/2 + 10
R = V/I
r/2+ 10 = 10/0.5
r = 20 ohm
EST Physics
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Answer C
ÊŽ R / d
1.9 x 10– 3 = ÊŽ x 0.6 / 0.2 x 10-3
ÊŽ = 0.63 x 10– 6 micrometer = 0.63 m
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Answer c
n2 / n1 = ÊŽ1/ ÊŽ 2 = y1/ y 2
1.5 / 1 = 1.9 / y 2 y2 = 1.26 mm
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Answer B
d = vi t + ½ at2
200 = 0 + ½ x 5 t2
t = 8.9 s
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Answer B
F = n / t = 120 / 60 = 2 v= F X ÊŽ = 2X 0.2 = 0.4 m/s
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Answer E
I = 6Sin 50 πt pure resistance means v,I are in same phase Sin 50 πt = 1
E = Pt = I2 R t = 62 x 4 x 20 = 2880 J
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Answer B
t1 = t2
d/15 = 250 – d /-10 t1 = 750/15 = 50 s
t 2 = 250 – 750 / -10 = 60 s
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Answer F
d = v delta t = -10 x 10 = -100 I meters
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Answer A
Q= 72 C1= 6 C2 = 4 C Total = 10
72/10 = 7.2 for each part
6×7.2 = 43.2 microcoloumb
4×7.2 = 28.8 microcoloumb
EST Physics
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Answer B
V= Q/C = 72/10 = 7.2 volt
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Answer D
G = G M /r 2 = 6.67×10-11 x 5.98 x 1024 / ( 6700 x 103 )2 = 8.8 m/s2
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Answer B
Focal length = distance between focus and center of curvature =20 cm
Since 2F=40 cm
It is given that object is kept at 60 cm from center of curvature since object is beyond 2F.
Nature of image → Real and inverted
Size of image → Smaller
Position → Between F and 2F on other side of lens.
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Answer c
V= ÊŽ x f
330 = ÊŽ x 60×103
ÊŽ = 0.0055 m = 5.5 mm
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Answer c
W x o.4 = ( 350 x0.2 ) + ( 100 x 0.5 )= 300 N
EST Physics
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Answer A
d = Vi t + ½ g t2
14 = ½ x10 t2
t = root 2.8
30 = ½ x 10t2
T = root 6
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Answer c
Q LOST = Q GAINED
Mc
0.08 x 4200 x ( 70- t ) = 0.1 x4200 ( t – 28 )
336 ( 70 – t ) = 420 ( t – 28 )
0.8 ( 70 – t ) = t – 28
1.8 t = 56+ 28
t = 84/1.8 = 47 0 c
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Answer D
Horizontal component of velocity of aeroplane and horizontal component of velocity of bomb is same
The velocity of the bomb is unaffected by the vertical acceleration
EST Physics
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Answer c
2g h = vf2 – vi2
Vf = root 2 g h
Vf = vi + g t
Root 2gh = gt
T = root 2gh/g = root 2h/g
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Answer A
R t = 2+ ( ¼ + 1/6 + 1/10 )-1 = 3.9 ohm
I= V/R= 12/3.9 = 3 A V 2 OHM = IR = 3X2 = 6 VOLTS V REST = 6
I = V/R 10 OHM = 6/10 = 0.6 A
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Answer B
P= V2/ R
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Answer A
As unlike charges attract
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Answer E
T= BIAN sides of rectangular coil are parallel to the field
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Answer D
it will be halved as they are inversely proportional
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Answer A
= 633X10-9 X1/0.2 X 10-3 = 6.33X10-3 m
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Answer B
F= MV2/r M = 1000X4X104 /602 = 11.11 x103 kg
EST Physics
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Answer D
A = v2 /r = 602/1000 = 3.6 m/s2
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Answer A
The equivalent resistance of a group of resistors connected in parallel is less than any one of the resistors
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Answer E
The resistance which is short circuited will be eliminated from the circuit so the total resistance decreases and current intensity and voltage increases
R=V/I
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Answer D
Circuit consists of a resistance and a inductor coil
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Answer c
I= 5-2.5t t=0 I= 5
Emf = L / = 0.5 x5 /2 = 1.25 v
V= IR = 2.5 x0.8 = 2
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Answer D
V- emf =2- 1.25 = 0.75
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Answer B
EST Physics online
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Answer B
NP/NS = V big / V small 2000/NS = 240/12 NS =100
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Answer A
EW = h f c = h c/ÊŽ
3×1.6×10-19 = 6.6×10-34 x3x 108 / ÊŽ
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Answer D
Resonance occurs in a series circuit when the supply frequency causes the voltages across L and C equal and opposite in phase
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Answer A
F is inversely proportional with square distance 1/22 = ¼
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Answer A
As it’s a scalar quantity having magnitude only
EST Physics
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Answer A
Mechanical energy = pe at the top = mgh = 0.4 x10x2= 8 J
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Answer D
When 2 waves slightly different in frequency interfere they form beats
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Answer D
m = 500/10 = 50 Kg F= ma = 50 x 2= 100 N
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Answer A
B= µ I / 2Ï€ d = 4 Ï€x 10– 7 x2 /2Ï€ x 0.4 = 10-6 T
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Answer C
Force is directly proportional with acceleration according to Newton’s second law
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Answer B
µ mg = 12 µ = 12/20 =0.6
EST Physics
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Answer C
2 ad = VF2 –VI2
2 a x10 = s2 – 102 a= -3.75 m/s2
W = F d = ma d= 8×3.75 x 10 = 300 j
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Answer B
0=2×100-3000 V
-200 = -3000 V
V= 0.06 m/s
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Answer C
V= F X ÊŽ When changing medium v is directly proportional with wave length
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Answer B
M1v1+ m2v2 = (m1+ m2 ) v 12
2v+ 0 = 3 v12 2v= 3v12 v12= 2/3 v
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Answer B
The kinetic energy decreases with time
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Answer B
P1V1/T1 = P2V2/T2
300 V/( 23+273) = P2 V/( 323+273 )2
P2=1200 Kpa
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Answer D
Its velocity is changing direction
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Answer C
Speed of light is constant in any reference frame
EST Physics
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Answer B
W= V/r L = I W
W is inversely proportional with I
W1/W2 = I2/I1 20/W2=5/15 W2=60
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Answer A
R= VIX T = VI COS Ï´.T
L1/L2=COS π/COS π/6 L2 = root 3/2 L
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Answer B
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Answer D
V= Xm W cos W t = – 3.5 x10-2 x( 2Ï€ /Ï€ )x5 cos 2Ï€ = – 0.47 m/s
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Answer B
a = V WCOS WT a = -1.5 m/s2
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Answer B
U= ½ K X2
T= 2 π ROOT m/ k
Ï€/5 = 2Ï€ root o.5 /k k = 50
u=0 .5 x50 x( 1.5×10-2)2 u= 0.0056 = 55 mj
Best of luck Mrs Hadil Fayzi EST physics instructor
contact information +201114433760