EST Physics
Egyptian scholastic test (EST) two Physics real tests questions with explanation for free. EST Physics test is prepared by Mrs. Hadil Fayzi.
Physics EST real test is available on https://sat-act-est.com/.
EST Physics question 1-4
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Answer A The temperature of the solid rises as heat is added, Q = mcsΔT ( EST Physics)
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Answer E
When the entire substance has become a liquid, the heat added, Q = mclΔT, raises the temperature until the substance reaches its boiling point. At the boiling point, the temperature is again constant while the heat of vaporization, Q = mLV, converts the substance into a gas
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Answer B
When the substance reaches its melting point, the temperature becomes constant while the heat of fusion, Q = mLF, is added to convert the solid into a liquid.
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Answer D
At the boiling point, the temperature is again constant while
The heat of vaporization, Q = mLV, converts the substance into a gas.
Question 5-6 EST physics
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Req = 2+( 1/12+ 1/6)-1= 6 ohm
I=V/R=18/6=3 A
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Answer A
V=IR = 3X2= 6V (EST physics rules )
EST Physics Questions 7-9
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The equivalent resistance for resistors in series, Rs, is simply the sum of the individual resistances and its greater than any individual resistance.
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Answer c
The equivalent resistance for resistors in parallel, RP, is more complicated than for resistors in series. Parallel resistors are added together so that the sum of their individual reciprocals equals the reciprocal of the total resistance, the equivalent resistance is less than any individual resistance
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Answer D
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1/Req= 1/12+1/6
Req= 4 ohm
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Answer C
Bulbs are connected in parallel and checking other lamps or other circuit breakers is useless so, it is recommended to develop a new hypothesis for why the lights do not turn on
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Answer C
For the given oscillator, the mechanical energy at any time is :
EM= 1/2mv2+1/2Kx2 = constant derive with respect to time to get :
Mvv’ + KXX’ = 0 , x’=v and v’= x’’
So m x’’+ Kx= 0 divide by m
x’’+k/m x = 0
x’’+ 2x= 0 where k/m = 2
EST physics
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Answer B
25 years = 25x12x30x24x60 = 12960000min
60 beats min
x 12960000 min x= 7.88×108 beats
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Answer A
Alpha particles have the minimum penetration power due to its large mass
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Answer A
because they have magnitude and no direction ( EST Physics)
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Answer C
t= d/v = 8/4 = 2 sec
EST Physics real test with explanation
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Answer E
Vf=Vi+at = 3+2×4=11 m/s
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Answer D
d= vit + 1/2at2 = ( 3×4)+(1/2x2x42 )= 28 m
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d= vit + 1/2gt2
3= 0 + 1/2x 10 x t2
t=0.77 sec
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Answer E
2gd=vf2 – vi2
2(-10) = 22 – 82 d= 3 m
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Answer B
d = 2+ 62 = 10 m
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Answer A
2ad = vf2 – vi2
2XaX2= 4-0 a = 1 f=ma = 20×1 = 20 N
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Answer A
2gd = vf2 – vi2
2x10xd=4-0
D = 4/20 = 0.2 m
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Answer B
M1v1+m2v2 =(m1+m2)v’
2000×15 + 0 + ( 2000 + 4000 ) v’
V’= 5 m/s
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Answer d
At highest point the vertical velocity of the object will be zero and the whole velocity will be along the horizontal direction ,so the acceleration on the particle during the flight will be due to gravity ,so direction of acceleration will be vertical downward at highest point
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Answer B
At highest point the vertical velocity of the object will be zero and the whole velocity will be along the horizontal direction so it’ll be the horizontal component v0 cos
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Answer A
The velocity of projectile on reaching ground depends upon the initial velocity in x direction no force is acting on body so it’ll move with constant velocity
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Answer E
The direction of acceleration is the same as direction of force, regardless the direction of motion
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Answer d
Fnet = 2 + (2 )2= 4 N
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Answer c
tan = 6/2 = 60 clockwise
EST Physics real test with explanation
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Answer A
d = vit +1/2 at2
3= 0 + ½ a 22 a= 1.5 m/s2
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Answer c
∑ f = mg sin30 – µ N N= Mg cos 30
1.5 = 10 sin 30 – µ x 10 cos 30 µ = o.23
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Answer A
To calculate the mass defect add up the masses of each proton and of each neutron that make up the nucleus then subtract the actual mass of the nucleus from the combined mass of the components
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Answer E
V= root GM/ R = -11x6.6×1024 / 1×107 = 5×103 m/s
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Answer C
F= T- W
ma = T – mg
10×4 = T – 10X10 T= 140 N
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Answer C
Force is acting on 2 boxes so their masses will be added together
EST Physics real test with explanation
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Answer B
Force of air resistance and force of gravity are directed downward but the force of ball is directed upward
Action and reaction
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Answer E
As the slope of curve is positive
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Answer c
As the slope of curve is negative
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Answer D
F= kx
10=k x 0.01 k= 1000
U= ½ kx2 = ½ x 1000 x ( 0.05 )2
= 1.25 j
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Answer A
To generate centripetal force from friction
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Answer A
Req= ( ¼ + ½ )-1 + 0.67 + 3 = 5 ohm symbol M means a battery in opposite direction I= V/R = 12-2 /5 = 2 A
EST physics real test
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Answer C
Because force of friction is opposite to direction of motion
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Answer D
W= mgh + fd = ( 20×10 )+ ( 20 x 20 ) = 600 j
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Answer A
K= ( F-32 )5/9 + 273 = (95-32 )5/9 + 273 = 308
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Answer D
Mgh = 200x10x50 = 100000 j
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Answer B
Efficiency = 50 -35 /50 = 0.3
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Answer c
+ W W= P 2.5 x 105 ( 2×104– 3×10-3)= 700 j
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Answer D
F= k x
3×10 = k x ( 7.5×10-2 ) k= 400 N/m
EST Physics real test
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Answer c
ÊŽ =v/f = 3×108 / 1×109 = 0.3 m
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Answer B
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Answer B
T= 2Ï€ = 2Ï€ -3 / 72 =0.10466
F=1/T f= 9.5 Hz
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Answer D
L= n ÊŽ/2 ÊŽ = 2 n= 2
ÊŽ = 4 n= 1 L= 2 m
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Answer A
I= P/ area = p/4Ï€r2 p= 5.5×10-7x4 Ï€ x 42 = 3.52×10-5 Ï€
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Answer A
F=nv/4l = 1×346 /4xo.5 = 173 Hz
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Answer E
M = d0 / di = 10/5 = 2
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Answer D
hi/h0 = -di/do di= 50 cm 1.5/h0 = – 25 / -50
1/f= 1/d0 + 1/di h0 = 3 cm
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Answer A
Green + red = yellow
EST Physics real test
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Answer C
n = sinÏ´i/sin Ï´r 2.419 = sin 60 / sinÏ´r Ï´r=sin-1 ( 0.2 )
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Answer A
Sin ϴc = 1/n ϴc α 1/n
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Answer D
m ÊŽ = d sin Ï´ 2 ÊŽ = 3×10-5 sin 30 ÊŽ = 7.5 x 1011 m = 7.5 x103 nm
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Answer D
m ÊŽ = d sin Ï´
1x500x10-9 = 1000000 sinÏ´ Ï´ = zero
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Answer A
Ra228-4 = 224 Ra 90-2 = 88
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Answer B
I= Q/t = 2.5×10-3 / 5 x 10-3 = 0.5 A
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Answer D
E= k Q /r2 E1= 9×109 x 60 x 10-9 / 0.032 = 6×105 N/c
E2 = 9×109 x40 x 10-9 / 0.032= 4X105 N/C
= E2- E1 = 2X105 N/C
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Answer E
Electric force is a repulsive or attractive interactions between any two charged bodies
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Answer D
V= Ed = 75×10 = 750 v v =w/q w = 750 x1.6×10-19 j
EST Physics real test
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Answer B
Q=cv
18×10-12 = 6×10-6 x v v= 3×10-6 v
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Answer c
P = v2 /R R = 0.62 /0.1 = 3.6 ohm
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Answer A
The most massive radiation particle is alpha particle its mass is 4 amu while electron has the lowest mass
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Answer E
F= q v B sin 90 = 0.04 x 2 x 104 x o.1= 80 N
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Answer B
E = hf
((-1.51) – (-3.4))1.6x 10-19 = 6×10-34 x f
F= 5.04 x 1014 Hz
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Answer c
F= q v B
11×10-19 = 1.6 x10– 19 x v x 5.5 x 10-5
V= 1.25 x 105 m/s
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Answer c
F = BIL
12×10-2 = 2×10-4 x 12 x L L= 50 m
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Answer c
E =
E = A
10 -3 = O.O82 X (1.5-0.5)/
Written by Hadil Fayzi
For questions about Est physics +201114433760 Mrs Hadil