EST Physics
Egyptian scholastic test (EST) two Physics real tests questions with explanation for free. EST Physics test is prepared by Mrs. Hadil Fayzi.
Physics EST real test is available on https://sat-act-est.com/.
EST Physics question 1-4
Answer A The temperature of the solid rises as heat is added, Q = mcsΔT ( EST Physics)
Answer E
When the entire substance has become a liquid, the heat added, Q = mclΔT, raises the temperature until the substance reaches its boiling point. At the boiling point, the temperature is again constant while the heat of vaporization, Q = mLV, converts the substance into a gas
Answer B
When the substance reaches its melting point, the temperature becomes constant while the heat of fusion, Q = mLF, is added to convert the solid into a liquid.
Answer D
At the boiling point, the temperature is again constant while
The heat of vaporization, Q = mLV, converts the substance into a gas.
Question 5-6 EST physics
Req = 2+( 1/12+ 1/6)-1= 6 ohm
I=V/R=18/6=3 A
Answer A
V=IR = 3X2= 6V (EST physics rules )
EST Physics Questions 7-9
The equivalent resistance for resistors in series, Rs, is simply the sum of the individual resistances and its greater than any individual resistance.
Answer c
The equivalent resistance for resistors in parallel, RP, is more complicated than for resistors in series. Parallel resistors are added together so that the sum of their individual reciprocals equals the reciprocal of the total resistance, the equivalent resistance is less than any individual resistance
Answer D
1/Req= 1/12+1/6
Req= 4 ohm
Answer C
Bulbs are connected in parallel and checking other lamps or other circuit breakers is useless so, it is recommended to develop a new hypothesis for why the lights do not turn on
Answer C
For the given oscillator, the mechanical energy at any time is :
EM= 1/2mv2+1/2Kx2 = constant derive with respect to time to get :
Mvv’ + KXX’ = 0 , x’=v and v’= x’’
So m x’’+ Kx= 0 divide by m
x’’+k/m x = 0
x’’+ 2x= 0 where k/m = 2
EST physics
Answer B
25 years = 25x12x30x24x60 = 12960000min
60 beats min
x 12960000 min x= 7.88×108 beats
Answer A
Alpha particles have the minimum penetration power due to its large mass
Answer A
because they have magnitude and no direction ( EST Physics)
Answer C
t= d/v = 8/4 = 2 sec
EST Physics real test with explanation
Answer E
Vf=Vi+at = 3+2×4=11 m/s
Answer D
d= vit + 1/2at2 = ( 3×4)+(1/2x2x42 )= 28 m
d= vit + 1/2gt2
3= 0 + 1/2x 10 x t2
t=0.77 sec
Answer E
2gd=vf2 – vi2
2(-10) = 22 – 82 d= 3 m
Answer B
d = 2+ 62 = 10 m
Answer A
2ad = vf2 – vi2
2XaX2= 4-0 a = 1 f=ma = 20×1 = 20 N
Answer A
2gd = vf2 – vi2
2x10xd=4-0
D = 4/20 = 0.2 m
Answer B
M1v1+m2v2 =(m1+m2)v’
2000×15 + 0 + ( 2000 + 4000 ) v’
V’= 5 m/s
Answer d
At highest point the vertical velocity of the object will be zero and the whole velocity will be along the horizontal direction ,so the acceleration on the particle during the flight will be due to gravity ,so direction of acceleration will be vertical downward at highest point
Answer B
At highest point the vertical velocity of the object will be zero and the whole velocity will be along the horizontal direction so it’ll be the horizontal component v0 cos
Answer A
The velocity of projectile on reaching ground depends upon the initial velocity in x direction no force is acting on body so it’ll move with constant velocity
Answer E
The direction of acceleration is the same as direction of force, regardless the direction of motion
Answer d
Fnet = 2 + (2 )2= 4 N
Answer c
tan = 6/2 = 60 clockwise
EST Physics real test with explanation
Answer A
d = vit +1/2 at2
3= 0 + ½ a 22 a= 1.5 m/s2
Answer c
∑ f = mg sin30 – µ N N= Mg cos 30
1.5 = 10 sin 30 – µ x 10 cos 30 µ = o.23
Answer A
To calculate the mass defect add up the masses of each proton and of each neutron that make up the nucleus then subtract the actual mass of the nucleus from the combined mass of the components
Answer E
V= root GM/ R = -11x6.6×1024 / 1×107 = 5×103 m/s
Answer C
F= T- W
ma = T – mg
10×4 = T – 10X10 T= 140 N
Answer C
Force is acting on 2 boxes so their masses will be added together
EST Physics real test with explanation
Answer B
Force of air resistance and force of gravity are directed downward but the force of ball is directed upward
Action and reaction
Answer E
As the slope of curve is positive
Answer c
As the slope of curve is negative
Answer D
F= kx
10=k x 0.01 k= 1000
U= ½ kx2 = ½ x 1000 x ( 0.05 )2
= 1.25 j
Answer A
To generate centripetal force from friction
Answer A
Req= ( ¼ + ½ )-1 + 0.67 + 3 = 5 ohm symbol M means a battery in opposite direction I= V/R = 12-2 /5 = 2 A
EST physics real test
Answer C
Because force of friction is opposite to direction of motion
Answer D
W= mgh + fd = ( 20×10 )+ ( 20 x 20 ) = 600 j
Answer A
K= ( F-32 )5/9 + 273 = (95-32 )5/9 + 273 = 308
Answer D
Mgh = 200x10x50 = 100000 j
Answer B
Efficiency = 50 -35 /50 = 0.3
Answer c
+ W W= P 2.5 x 105 ( 2×104– 3×10-3)= 700 j
Answer D
F= k x
3×10 = k x ( 7.5×10-2 ) k= 400 N/m
EST Physics real test
Answer c
ÊŽ =v/f = 3×108 / 1×109 = 0.3 m
Answer B
Answer B
T= 2Ï€ = 2Ï€ -3 / 72 =0.10466
F=1/T f= 9.5 Hz
Answer D
L= n ÊŽ/2 ÊŽ = 2 n= 2
ÊŽ = 4 n= 1 L= 2 m
Answer A
I= P/ area = p/4Ï€r2 p= 5.5×10-7x4 Ï€ x 42 = 3.52×10-5 Ï€
Answer A
F=nv/4l = 1×346 /4xo.5 = 173 Hz
Answer E
M = d0 / di = 10/5 = 2
Answer D
hi/h0 = -di/do di= 50 cm 1.5/h0 = – 25 / -50
1/f= 1/d0 + 1/di h0 = 3 cm
Answer A
Green + red = yellow
EST Physics real test
Answer C
n = sinÏ´i/sin Ï´r 2.419 = sin 60 / sinÏ´r Ï´r=sin-1 ( 0.2 )
Answer A
Sin ϴc = 1/n ϴc α 1/n
Answer D
m ÊŽ = d sin Ï´ 2 ÊŽ = 3×10-5 sin 30 ÊŽ = 7.5 x 1011 m = 7.5 x103 nm
Answer D
m ÊŽ = d sin Ï´
1x500x10-9 = 1000000 sinÏ´ Ï´ = zero
Answer A
Ra228-4 = 224 Ra 90-2 = 88
Answer B
I= Q/t = 2.5×10-3 / 5 x 10-3 = 0.5 A
Answer D
E= k Q /r2 E1= 9×109 x 60 x 10-9 / 0.032 = 6×105 N/c
E2 = 9×109 x40 x 10-9 / 0.032= 4X105 N/C
= E2- E1 = 2X105 N/C
Answer E
Electric force is a repulsive or attractive interactions between any two charged bodies
Answer D
V= Ed = 75×10 = 750 v v =w/q w = 750 x1.6×10-19 j
EST Physics real test
Answer B
Q=cv
18×10-12 = 6×10-6 x v v= 3×10-6 v
Answer c
P = v2 /R R = 0.62 /0.1 = 3.6 ohm
Answer A
The most massive radiation particle is alpha particle its mass is 4 amu while electron has the lowest mass
Answer E
F= q v B sin 90 = 0.04 x 2 x 104 x o.1= 80 N
Answer B
E = hf
((-1.51) – (-3.4))1.6x 10-19 = 6×10-34 x f
F= 5.04 x 1014 Hz
Answer c
F= q v B
11×10-19 = 1.6 x10– 19 x v x 5.5 x 10-5
V= 1.25 x 105 m/s
Answer c
F = BIL
12×10-2 = 2×10-4 x 12 x L L= 50 m
Answer c
E =
E = A
10 -3 = O.O82 X (1.5-0.5)/
Written by Hadil Fayzi
For questions about Est physics +201114433760 Mrs Hadil